Optimal. Leaf size=391 \[ \frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}-\frac{63 d^{11/2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}-\frac{63 d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}+1\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5} \]
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Rubi [A] time = 0.473032, antiderivative size = 391, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 10, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.357, Rules used = {28, 288, 290, 329, 211, 1165, 628, 1162, 617, 204} \[ \frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}-\frac{63 d^{11/2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}-\frac{63 d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}+1\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5} \]
Antiderivative was successfully verified.
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Rule 28
Rule 288
Rule 290
Rule 329
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int \frac{(d x)^{11/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^3} \, dx &=b^6 \int \frac{(d x)^{11/2}}{\left (a b+b^2 x^2\right )^6} \, dx\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}+\frac{1}{20} \left (9 b^4 d^2\right ) \int \frac{(d x)^{7/2}}{\left (a b+b^2 x^2\right )^5} \, dx\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}+\frac{1}{64} \left (9 b^2 d^4\right ) \int \frac{(d x)^{3/2}}{\left (a b+b^2 x^2\right )^4} \, dx\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{1}{256} \left (3 d^6\right ) \int \frac{1}{\sqrt{d x} \left (a b+b^2 x^2\right )^3} \, dx\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{\left (21 d^6\right ) \int \frac{1}{\sqrt{d x} \left (a b+b^2 x^2\right )^2} \, dx}{2048 a b}\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}+\frac{\left (63 d^6\right ) \int \frac{1}{\sqrt{d x} \left (a b+b^2 x^2\right )} \, dx}{8192 a^2 b^2}\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}+\frac{\left (63 d^5\right ) \operatorname{Subst}\left (\int \frac{1}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{4096 a^2 b^2}\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}+\frac{\left (63 d^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a} d-\sqrt{b} x^2}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{8192 a^{5/2} b^2}+\frac{\left (63 d^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a} d+\sqrt{b} x^2}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{8192 a^{5/2} b^2}\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}-\frac{\left (63 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d}}{\sqrt [4]{b}}+2 x}{-\frac{\sqrt{a} d}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{d x}\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}-\frac{\left (63 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d}}{\sqrt [4]{b}}-2 x}{-\frac{\sqrt{a} d}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{d x}\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}+\frac{\left (63 d^6\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a} d}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{d x}\right )}{16384 a^{5/2} b^{7/2}}+\frac{\left (63 d^6\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a} d}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{d x}\right )}{16384 a^{5/2} b^{7/2}}\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}-\frac{63 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}+\frac{\left (63 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}-\frac{\left (63 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}\\ &=-\frac{d (d x)^{9/2}}{10 b \left (a+b x^2\right )^5}-\frac{9 d^3 (d x)^{5/2}}{160 b^2 \left (a+b x^2\right )^4}-\frac{3 d^5 \sqrt{d x}}{128 b^3 \left (a+b x^2\right )^3}+\frac{3 d^5 \sqrt{d x}}{1024 a b^3 \left (a+b x^2\right )^2}+\frac{21 d^5 \sqrt{d x}}{4096 a^2 b^3 \left (a+b x^2\right )}-\frac{63 d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{8192 \sqrt{2} a^{11/4} b^{13/4}}-\frac{63 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}+\frac{63 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{16384 \sqrt{2} a^{11/4} b^{13/4}}\\ \end{align*}
Mathematica [A] time = 0.18397, size = 337, normalized size = 0.86 \[ \frac{d^5 \sqrt{d x} \left (\frac{9240 \sqrt [4]{b}}{a^2 \left (a+b x^2\right )}-\frac{49152 a^2 \sqrt [4]{b}}{\left (a+b x^2\right )^5}-\frac{3465 \sqrt{2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{a^{11/4} \sqrt{x}}+\frac{3465 \sqrt{2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{a^{11/4} \sqrt{x}}-\frac{6930 \sqrt{2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{a^{11/4} \sqrt{x}}+\frac{6930 \sqrt{2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}+1\right )}{a^{11/4} \sqrt{x}}-\frac{327680 b^{9/4} x^4}{\left (a+b x^2\right )^5}-\frac{196608 a b^{5/4} x^2}{\left (a+b x^2\right )^5}+\frac{5280 \sqrt [4]{b}}{a \left (a+b x^2\right )^2}+\frac{3840 \sqrt [4]{b}}{\left (a+b x^2\right )^3}+\frac{3072 a \sqrt [4]{b}}{\left (a+b x^2\right )^4}\right )}{1802240 b^{13/4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.069, size = 339, normalized size = 0.9 \begin{align*} -{\frac{63\,{d}^{15}{a}^{2}}{4096\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{5}{b}^{3}}\sqrt{dx}}-{\frac{189\,{d}^{13}a}{2560\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{5}{b}^{2}} \left ( dx \right ) ^{{\frac{5}{2}}}}-{\frac{287\,{d}^{11}}{2048\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{5}b} \left ( dx \right ) ^{{\frac{9}{2}}}}+{\frac{3\,{d}^{9}}{128\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{5}a} \left ( dx \right ) ^{{\frac{13}{2}}}}+{\frac{21\,{d}^{7}b}{4096\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{5}{a}^{2}} \left ( dx \right ) ^{{\frac{17}{2}}}}+{\frac{63\,{d}^{5}\sqrt{2}}{32768\,{a}^{3}{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\ln \left ({ \left ( dx+\sqrt [4]{{\frac{a{d}^{2}}{b}}}\sqrt{dx}\sqrt{2}+\sqrt{{\frac{a{d}^{2}}{b}}} \right ) \left ( dx-\sqrt [4]{{\frac{a{d}^{2}}{b}}}\sqrt{dx}\sqrt{2}+\sqrt{{\frac{a{d}^{2}}{b}}} \right ) ^{-1}} \right ) }+{\frac{63\,{d}^{5}\sqrt{2}}{16384\,{a}^{3}{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\arctan \left ({\sqrt{2}\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{a{d}^{2}}{b}}}}}}+1 \right ) }+{\frac{63\,{d}^{5}\sqrt{2}}{16384\,{a}^{3}{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\arctan \left ({\sqrt{2}\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{a{d}^{2}}{b}}}}}}-1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.4187, size = 1150, normalized size = 2.94 \begin{align*} \frac{1260 \,{\left (a^{2} b^{8} x^{10} + 5 \, a^{3} b^{7} x^{8} + 10 \, a^{4} b^{6} x^{6} + 10 \, a^{5} b^{5} x^{4} + 5 \, a^{6} b^{4} x^{2} + a^{7} b^{3}\right )} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{1}{4}} \arctan \left (-\frac{\sqrt{d x} a^{8} b^{10} d^{5} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{3}{4}} - \sqrt{a^{6} b^{6} \sqrt{-\frac{d^{22}}{a^{11} b^{13}}} + d^{11} x} a^{8} b^{10} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{3}{4}}}{d^{22}}\right ) + 315 \,{\left (a^{2} b^{8} x^{10} + 5 \, a^{3} b^{7} x^{8} + 10 \, a^{4} b^{6} x^{6} + 10 \, a^{5} b^{5} x^{4} + 5 \, a^{6} b^{4} x^{2} + a^{7} b^{3}\right )} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{1}{4}} \log \left (63 \, a^{3} b^{3} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{1}{4}} + 63 \, \sqrt{d x} d^{5}\right ) - 315 \,{\left (a^{2} b^{8} x^{10} + 5 \, a^{3} b^{7} x^{8} + 10 \, a^{4} b^{6} x^{6} + 10 \, a^{5} b^{5} x^{4} + 5 \, a^{6} b^{4} x^{2} + a^{7} b^{3}\right )} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{1}{4}} \log \left (-63 \, a^{3} b^{3} \left (-\frac{d^{22}}{a^{11} b^{13}}\right )^{\frac{1}{4}} + 63 \, \sqrt{d x} d^{5}\right ) + 4 \,{\left (105 \, b^{4} d^{5} x^{8} + 480 \, a b^{3} d^{5} x^{6} - 2870 \, a^{2} b^{2} d^{5} x^{4} - 1512 \, a^{3} b d^{5} x^{2} - 315 \, a^{4} d^{5}\right )} \sqrt{d x}}{81920 \,{\left (a^{2} b^{8} x^{10} + 5 \, a^{3} b^{7} x^{8} + 10 \, a^{4} b^{6} x^{6} + 10 \, a^{5} b^{5} x^{4} + 5 \, a^{6} b^{4} x^{2} + a^{7} b^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.17385, size = 467, normalized size = 1.19 \begin{align*} \frac{1}{163840} \, d^{4}{\left (\frac{630 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} + 2 \, \sqrt{d x}\right )}}{2 \, \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}}}\right )}{a^{3} b^{4}} + \frac{630 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} - 2 \, \sqrt{d x}\right )}}{2 \, \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}}}\right )}{a^{3} b^{4}} + \frac{315 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \log \left (d x + \sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} \sqrt{d x} + \sqrt{\frac{a d^{2}}{b}}\right )}{a^{3} b^{4}} - \frac{315 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \log \left (d x - \sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} \sqrt{d x} + \sqrt{\frac{a d^{2}}{b}}\right )}{a^{3} b^{4}} + \frac{8 \,{\left (105 \, \sqrt{d x} b^{4} d^{11} x^{8} + 480 \, \sqrt{d x} a b^{3} d^{11} x^{6} - 2870 \, \sqrt{d x} a^{2} b^{2} d^{11} x^{4} - 1512 \, \sqrt{d x} a^{3} b d^{11} x^{2} - 315 \, \sqrt{d x} a^{4} d^{11}\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{5} a^{2} b^{3}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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